X Total Shapes

PROBLEM :

Given N * M string array of O's and X's
Return the number of 'X' total shapes. 'X' shape consists of one or more adjacent X's (diagonals not included).

Example (1):

OOOXOOO
OXXXXXO
OXOOOXO

answer is 1 , shapes are  :
(i)     X
    X X X X
    X     X


Example (2):
XXX
OOO
XXX

answer is 2, shapes are
(i)  XXX
(ii) XXX

Input:
The first line of input takes the number of test cases, T.
Then T test cases follow. Each of the T test cases takes 2 input lines.
The first line of each test case have two integers N and M.The second line of N space separated strings follow which indicate the elements in the array.

Output:
Print number of shapes.

Constraints:
1<=T<=100
1<=N,M<=50

Example:
Input:
2
4 7
OOOOXXO OXOXOOX XXXXOXO OXXXOOO
10 3
XXO OOX OXO OOO XOX XOX OXO XXO XXX OOO

Output:
4
6

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std ;
#include <string.h>
#define MAX 50

int XTotalShapes(char [][MAX],int ,int ) ;
void DFSvisitAll(char [][MAX],int ,int ,bool [][MAX],int ,int ) ;
bool IsConnected(char [][MAX],int ,int ,bool [][MAX],int ,int ) ;

int main()
{
int t ;
cin>>t ;
while(t--)
{
char mat[MAX][MAX] ;
int row,col ;
cin>>row>>col ;

for(int i=0;i<row;i++)
for(int j=0;j<col;j++)
cin>>mat[i][j] ;

cout<<XTotalShapes(mat,row,col)<<endl  ;
}
return 0 ;
}

int XTotalShapes(char mat[][MAX],int row,int col)
{
bool visited[MAX][MAX] ;
memset(visited,0, sizeof(visited));

int count=0 ;
for(int i=0;i<row;i++)
for(int j=0;j<col;j++)
if(!visited[i][j]&&mat[i][j]=='X')
{
count++ ;
DFSvisitAll(mat,row,col,visited,i,j) ;
}
return count ;
}

void DFSvisitAll(char mat[][MAX],int row,int col,bool visited[][MAX],int currR,int currC)
{
visited[currR][currC]=true ;

int t1[]={-1,0,0,1} ;
    int t2[]={0,-1,1,0} ;
   
    for(int k=0;k<4;k++)
    {
    if(IsConnected(mat,row,col,visited,currR+t1[k],currC+t2[k]))
    DFSvisitAll(mat,row,col,visited,currR+t1[k],currC+t2[k]) ;
}
}

bool IsConnected(char mat[][MAX],int row,int col,bool visited[][MAX],int currR,int currC)
{
return (currR>=0&&currC>=0)&&(currR<row&&currC<col)&&(mat[currR][currC]=='X'&&!visited[currR][currC]) ;
}

--------------------------------------------------------------------------------

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