Floyd Warshall Algorithm

PROBLEM :

The problem is to find shortest distances between every pair of vertices in a given edge weighted directed Graph.

Input:
The first line of input contains an integer T denoting the no of test cases . Then T test cases follow . The first line of each test case contains an integer V denoting the size of the adjacency matrix  and in the next line are V*V space separated values of the matrix (graph) .

Output:
For each test case output will be V*V space separated integers where the i-jth integer denote the shortest distance of ith vertex from jth vertex.

Constraints:
1<=T<=20
1<=V<=20
-1000<=graph[][]<=1000

Example:
Input
2
2
0 25 25 0
3
0 1 43 1 0 6 43 6 0

Output
0 25 25 0
0 1 7 1 0 6 7 6 0

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
#define MAX 1000
void FloydWarshall(int graph[MAX][MAX],int ) ;

int main()
{
int t ;
cin>>t ;

while(t--)
{
   int no ;
   cin>>no ;
 
   int graph[MAX][MAX] ;
   for(int i=0;i<no;i++)
       for(int j=0;j<no;j++)
           cin>>graph[i][j] ;
         
   FloydWarshall(graph,no) ;
   cout<<endl ;
}
return 0;
}

void FloydWarshall(int graph[MAX][MAX],int no)
{
    int path[MAX][MAX] ;
   
    for(int i=0;i<no;i++)
        for(int j=0;j<no;j++)
            path[i][j]=graph[i][j] ;
           
    for(int k=0;k<no;k++)
    {
        for(int j=0;j<no;j++)
        {
            for(int i=0;i<no;i++)
            {
                if(path[i][k] + path[k][j] < path[i][j])
                    path[i][j] = path[i][k] + path[k][j] ;
            }
        }
    }
   
    for(int i=0;i<no;i++)
  for(int j=0;j<no;j++)
      cout<<path[i][j]<<" " ;
   
}

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