Subtree of Another Tree @LeetCode

PROBLEM :

Given two non-empty binary trees s and t, check whether tree t has exactly the same structure and node values with a subtree of s. A subtree of s is a tree consists of a node in s and all of this node's descendants. The tree s could also be considered as a subtree of itself.

Example 1:
Given tree s:

     3
    / \
   4   5
  / \
 1   2
Given tree t:
   4
  / \
 1   2
Return true, because t has the same structure and node values with a subtree of s.

Example 2:
Given tree s:

     3
    / \
   4   5
  / \
 1   2
    /
   0
Given tree t:
   4
  / \
 1   2

Return false.

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */

class Solution {
public:
    bool isSubtree(TreeNode* s, TreeNode* t) {
        if(!s)
            return false ;
       
        bool curr=false ;  
        if(s->val==t->val)
            curr=Check(s,t) ;
           
        if(curr)
            return true ;
        else
            return isSubtree(s->left,t)||isSubtree(s->right,t) ;
    }
   
    bool Check(TreeNode* org,TreeNode* copy){
        if(!org&&!copy)
            return true ;
       
        if(!org||!copy)
            return false ;
           
        return (org->val==copy->val)&&(Check(org->left,copy->left)&&(Check(org->right,copy->right))) ;
    }
};

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