Thief trying to escape
PROBLEM :
A thief trying to escape from a jail has to cross N walls each with varying heights. He climbs X feet every time. But, due to the slippery nature of those walls, every times he slips back by Y feet. Now the task is to calculate the total number of jumps required to cross all walls and escape from the jail.
Input:
The first line of input contains an integer T denoting the no of test cases. Then T test cases follow. Each test case contains two space separated integers X, Y, N. Then in the next line are N space separated values denoting the heights ( Ht[] ) of the walls.
Output:
For each test case in a new line print the total number of jumps.
Constraints:
1<=T<=100
1<= N, X, Y <=100
1<= Ht[] <=1000
Example:
Input:
2
10 1 1
5
4 1 5
6 9 11 4 5
Output:
1
12
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SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
#include<iostream>
using namespace std;
int main()
{
int t ;
cin>>t ;
while(t--){
int x,y,n ;
cin>>x>>y>>n ;
int arr[n] ;
for(int i=0;i<n;i++)
cin>>arr[i] ;
int count=0 ;
for(int i=0;i<n;i++){
if(arr[i]<=x)
count++ ;
else{
int temp=arr[i] ;
while(temp>x){
count++ ;
temp=temp-(x-y) ;
}
count++ ;
}
}
cout<<count<<endl ;
}
return 0;
}
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A thief trying to escape from a jail has to cross N walls each with varying heights. He climbs X feet every time. But, due to the slippery nature of those walls, every times he slips back by Y feet. Now the task is to calculate the total number of jumps required to cross all walls and escape from the jail.
Input:
The first line of input contains an integer T denoting the no of test cases. Then T test cases follow. Each test case contains two space separated integers X, Y, N. Then in the next line are N space separated values denoting the heights ( Ht[] ) of the walls.
Output:
For each test case in a new line print the total number of jumps.
Constraints:
1<=T<=100
1<= N, X, Y <=100
1<= Ht[] <=1000
Example:
Input:
2
10 1 1
5
4 1 5
6 9 11 4 5
Output:
1
12
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
#include<iostream>
using namespace std;
int main()
{
int t ;
cin>>t ;
while(t--){
int x,y,n ;
cin>>x>>y>>n ;
int arr[n] ;
for(int i=0;i<n;i++)
cin>>arr[i] ;
int count=0 ;
for(int i=0;i<n;i++){
if(arr[i]<=x)
count++ ;
else{
int temp=arr[i] ;
while(temp>x){
count++ ;
temp=temp-(x-y) ;
}
count++ ;
}
}
cout<<count<<endl ;
}
return 0;
}
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togloQfun_ha_1986 Ashley Allen click
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