Max Consecutive Ones @LeetCode
PROBLEM :
Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
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SIMPLE c++ IMPLEMENTATION :
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class Solution {
public:
int findMaxConsecutiveOnes(vector<int>& nums) {
int count,curr ;
curr=0 ;
count=0 ;
for(int i=0;i<nums.size();i++)
{
if(nums[i]==1)
curr++ ;
else{
if(curr>count)
count=curr ;
curr=0 ;
}
}
if(curr>count)
count=curr ;
return count ;
}
};
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Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:
The input array will only contain 0 and 1.
The length of input array is a positive integer and will not exceed 10,000
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
class Solution {
public:
int findMaxConsecutiveOnes(vector<int>& nums) {
int count,curr ;
curr=0 ;
count=0 ;
for(int i=0;i<nums.size();i++)
{
if(nums[i]==1)
curr++ ;
else{
if(curr>count)
count=curr ;
curr=0 ;
}
}
if(curr>count)
count=curr ;
return count ;
}
};
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