XOR of all elements

PROBLEM :

Given an array A[] having n positive elements. The task to create another array B[] such as B[i] is XOR of all elements of array A[] except A[i].

Examples:

Input : A[] = {2, 1, 5, 9}
Output : B[] = {13, 14, 10, 6}

Input : A[] = {2, 1, 3, 6}
Output : B[] = {4, 7, 5, 0}


Input:
The first line of input contains an integer T denoting the no of test cases. Then T test cases follow. Each test case contains an integer N denoting the size of the array. Then in the next line are N space separated values of the array (B[]).

Output:
For each test case in a new line print the space separated values of the new array (B[]).

Constraints:
1<=T<=100
1<=N<=100
1<=A[]<=100

Example:
2
4
2 1 5 9
4
2 1 3 6

Output:
13 14 10 6
4 7 5 0
   
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SIMPLE c++ IMPLEMENTATION :
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#include<iostream>
using namespace std;
int main()
{
    int t ;
    cin>>t ;
    while(t--){
        int no ;
        cin>>no ;
       
        int arr[no] ;
        for(int i=0;i<no;i++)
            cin>>arr[i] ;
           
        int barr[no]={0} ;
        int temp=0 ;
       
        for(int i=0;i<no;i++)
            temp=temp^arr[i] ;
           
        for(int i=0;i<no;i++)
            barr[i]=temp^arr[i] ;
           
        for(int i=0;i<no;i++)
            cout<<barr[i]<<" " ;
        cout<<endl ;
    }
    return 0;
}

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