Validate Binary Search Tree @LeetCode
PROBLEM :
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
Example 1:
2
/ \
1 3
Binary tree [2,1,3], return true.
Example 2:
1
/ \
2 3
Binary tree [1,2,3], return false.
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SIMPLE c++ IMPLEMENTATION :( Recursive Solution )
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isValidBST(TreeNode* root) {
return IsValidBSTree(root,NULL,NULL) ;
}
bool IsValidBSTree(TreeNode* root,TreeNode* min,TreeNode* max){
if(root==NULL)
return true ;
if(min&&root->val<=min->val)
return false ;
if(max&&root->val>=max->val)
return false ;
return (IsValidBSTree(root->left,min,root)&&IsValidBSTree(root->right,root,max)) ;
}
};
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Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
Example 1:
2
/ \
1 3
Binary tree [2,1,3], return true.
Example 2:
1
/ \
2 3
Binary tree [1,2,3], return false.
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :( Recursive Solution )
--------------------------------------------------------------------------------
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isValidBST(TreeNode* root) {
return IsValidBSTree(root,NULL,NULL) ;
}
bool IsValidBSTree(TreeNode* root,TreeNode* min,TreeNode* max){
if(root==NULL)
return true ;
if(min&&root->val<=min->val)
return false ;
if(max&&root->val>=max->val)
return false ;
return (IsValidBSTree(root->left,min,root)&&IsValidBSTree(root->right,root,max)) ;
}
};
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