Check if a number can be expressed as a sum of consecutive numbers

PROBLEM :

Given a number n, the task is to check whether it can be expressed as a sum of two or more consecutive numbers or not.

Examples:

Input  : n = 10
Output : 1
It can be expressed as sum of two consecutive
numbers 1 + 2 + 3 + 4.

Input  : n = 16
Output : 0
It cannot be expressed as sum of two consecutive
numbers.

Input  : n = 5
Output : 1
2 + 3 = 5


Input:
The first line contains 'T' denoting the number of test cases. Then follows description of test cases.
Each test case contains a single positive integer n.

Output:
Print "1" if number can be expressed as sum of consecutives else "0". (Without the double quotes)

Constraints:
1<=T<=200
0<=N<=10^18

Example:
Input :
2
4
5

Output :
0
1
   
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
bool SumConsecutives(long long ) ;
int main()
{
int t ;
cin>>t ;
while(t--){
   long long no ;
   cin>>no ;
   if(SumConsecutives(no))
       cout<<1 ;
   else
       cout<<0 ;
   cout<<endl ;
}
return 0;
}

bool SumConsecutives(long long no){
    if(no&&(no&(no-1)))
        return true ;
    return false ;
}

---------------------------------------------------------------------------------

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