Minimum Depth of Binary Tree @LeetCode
PROBLEM :
Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
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SIMPLE c++ IMPLEMENTATION :( Using Queue )
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(root==NULL)
return 0 ;
queue<TreeNode*> que ;
que.push(root) ;
int depth=0 ;
while(!que.empty()){
int n=que.size() ;
depth++ ;
while(n--){
TreeNode* node=que.front() ;
que.pop() ;
if(node->left==NULL&&node->right==NULL)
return depth ;
if(node->left)
que.push(node->left) ;
if(node->right)
que.push(node->right) ;
}
}
}
};
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :( Better Solution )
--------------------------------------------------------------------------------
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(root==NULL)
return 0 ;
int l=minDepth(root->left) ;
int r=minDepth(root->right) ;
return (l==0||r==0)?l+r+1:(l<r?l+1:r+1) ;
}
};
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Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :( Using Queue )
--------------------------------------------------------------------------------
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(root==NULL)
return 0 ;
queue<TreeNode*> que ;
que.push(root) ;
int depth=0 ;
while(!que.empty()){
int n=que.size() ;
depth++ ;
while(n--){
TreeNode* node=que.front() ;
que.pop() ;
if(node->left==NULL&&node->right==NULL)
return depth ;
if(node->left)
que.push(node->left) ;
if(node->right)
que.push(node->right) ;
}
}
}
};
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :( Better Solution )
--------------------------------------------------------------------------------
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(root==NULL)
return 0 ;
int l=minDepth(root->left) ;
int r=minDepth(root->right) ;
return (l==0||r==0)?l+r+1:(l<r?l+1:r+1) ;
}
};
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