Swap Nodes in Pairs
PROBLEM :
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
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SIMPLE c++ IMPLEMENTATION :
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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if(head==NULL||head->next==NULL)
return head ;
ListNode* one,*two,*three ;
one=head ;
two=one->next ;
three=two->next ;
one->next=NULL ;
two->next=one ;
if(three!=NULL)
one->next=swapPairs(three) ;
return two ;
}
};
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Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if(head==NULL||head->next==NULL)
return head ;
ListNode* one,*two,*three ;
one=head ;
two=one->next ;
three=two->next ;
one->next=NULL ;
two->next=one ;
if(three!=NULL)
one->next=swapPairs(three) ;
return two ;
}
};
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