Swap Nodes in Pairs

PROBLEM :

Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */

class Solution {
public:
    ListNode* swapPairs(ListNode* head) {
        if(head==NULL||head->next==NULL)
            return head ;
           
        ListNode* one,*two,*three ;
        one=head ;
        two=one->next ;
        three=two->next ;
       
        one->next=NULL ;
        two->next=one ;
       
        if(three!=NULL)
            one->next=swapPairs(three) ;
        return two ;
    }
};

---------------------------------------------------------------------------------

Comments

Popular posts from this blog

Count ways to N'th Stair(Order does not matter)

Replace all ‘0’ with ‘5’ in an input Integer

Chocolate Distribution Problem

Remove characters from the first string which are present in the second string

Primality Test ( CodeChef Problem code: PRB01 )