Power of 2

PROBLEM :
Given a positive integer N, check if N is a power of 2.

Input:
The first line contains 'T' denoting the number of test cases. Then follows description of test cases.
Each test case contains a single positive integer N.


Output:
Print "YES" if it is a power of 2 else "NO". (Without the double quotes)


Constraints:
1<=T<=100
0<=N<=10^18

Example:
Input :
2
1
98

Output :
YES
?NO

Explanation:  (2^0 == 1)

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int main()
 {
long long t,no,x=2,flag=0 ;
cin>>t ;
while(t--)
{
 
   cin>>no ;
   x=2 ;flag=0 ;
   if(no==1)
       { cout<<"YES"<<endl ;
           flag=1 ;}  
   else
   {
       while(x<no)
       {
           x=x*2 ;
       }
       if(x==no)
       {cout<<"YES"<<endl ;
       flag=1 ;}
   }
   if(flag==0)
   cout<<"NO"<<endl ;
}
return 0;
}

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