Number of Coins

PROBLEM :
Given a value V, if we want to make change for V cents,
and we have infinite supply of each of C = { C1, C2, .. , Cm} valued coins,
what is the minimum number of coins to make the change?

Input:
The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is V and N,V is the value of cents and N is the number of coins.
The second line of each test case contains N input C[i],value of available coins.

Output:
Print the minimum number of coins to make the change, if not possible print -1.

Constraints:
1 = T = 100
1 = V = 10000
1 = N = 50
1 = C[i] = 100

Example:
Input
1
7 2
2 1

Output
4

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<limits.h>
#include<iostream>
using namespace std;
int Number_Coins(int [],int ,int ) ;
int min_of(int ,int ) ;
#define max 100
int main()
{
    int t,no,i,k ;
    int arr[max] ;
    cin>>t ;
    while(t--)
    {
        cin>>k ;
        cin>>no ;
       
        for(i=0;i<no;i++)
            cin>>arr[i] ;
           
        cout<<Number_Coins(arr,no,k)<<endl ;
    }
return 0;
}

int Number_Coins(int arr[],int no,int final)
{
    int i,j ;
    int temp[final+1] ;
   
    temp[0]=0 ;
    for(i=1;i<=final;i++)
        temp[i]=INT_MAX-40 ;
       
    for(i=0;i<no;i++)
    {
        for(j=1;j<=final;j++)
        {
            if(j>=arr[i])
                temp[j]=min_of(temp[j],1+temp[j-arr[i]]) ;
        }
    }

    if(temp[final]>100000)
    return -1 ;
   
    return temp[final] ;
}

int min_of(int a,int b)
{
    return a<b?a:b ;
}

---------------------------------------------------------------------------------

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