Count ways to reach the n’th stair

PROBLEM :
There are n stairs, a person standing at the bottom wants to reach the top. The person can climb either 1 stair or 2 stairs at a time. Count the number of ways, the person can reach the top (order does matter).

Input:
The first line contains an integer 'T' denoting the total number of test cases. In each test cases, an integer N will be given.

Output:
Print number of possible ways to reach Nth stair. Answer your output % 10^9+7.

Constraints:
1<=T<=1000
1<=N<=100

Example:
Input:
3
4
10
24

Output:
5
89
75025

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SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
#include<math.h>
long long Count_nth_stair(long long ) ;
int main()
 {
int t ;
long long no ;
cin>>t ;
while(t--)
{
   cin>>no ;
 
   no=Count_nth_stair(no) ;
   cout<<no<<endl ;
}
return 0;
}

long long Count_nth_stair(long long no)
{
    long long arr[no+1] ;
    int i ;
   
    arr[0]=1 ;
    arr[1]=1 ;
   
    for(i=2;i<=no;i++)
        arr[i]=(arr[i-1]+arr[i-2])%1000000007 ;

    return arr[no] ;
}

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