Count Increasing Subsequences

PROBLEM :
Given an array of digits (values lie in range from 0 to 9). The task is to count all the sub sequences possible in array such that in each subsequence every digit is greater than its previous digits in the subsequence.

Examples:
Input : arr[] = {1, 2, 3, 4}
Output: 15
There are total increasing subsequences
{1}, {2}, {3}, {4}, {1,2}, {1,3}, {1,4},
{2,3}, {2,4}, {3,4}, {1,2,3}, {1,2,4},
{1,3,4}, {2,3,4}, {1,2,3,4}

Input : arr[] = {4, 3, 6, 5}
Output: 8
Sub-sequences are {4}, {3}, {6}, {5},
{4,6}, {4,5}, {3,6}, {3,5}

Input : arr[] = {3, 2, 4, 5, 4}
Output : 14
Sub-sequences are {3}, {2}, {4}, {3,4},
{2,4}, {5}, {3,5}, {2,5}, {4,5}, {3,2,5}
{3,4,5}, {4}, {3,4}, {2,4}
Input:

The first line of input contains an integer T denoting the number of test cases. The description of T test cases follows.
The first line of each test case contains a single integer N denoting the number of digits.
The second line contains N space-separated digits.

Output:
Count of all increasing subsequences in given array of digits.

Constraints:
1 = T = 30
1 = N = 500

Example:
Input:
2
5
3 2 4 5 4
3
1 2 4

Output:
14
7

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
long Count_Increasing_Subsequences(int [],int ) ;
int main()
{
int t,no,i ;
int arr[500] ;
cin>>t ;
while(t--)
{
   cin>>no ;
   for(i=0;i<no;i++)
       cin>>arr[i] ;
   cout<<Count_Increasing_Subsequences(arr,no)<<endl  ;
}
return 0;
}

long Count_Increasing_Subsequences(int arr[],int no)
{
    int i,j ;
    int temp[no] ;
    long sum ;
   
    for(i=0;i<no;i++)
        temp[i]=1 ;
       
    for(i=1;i<no;i++)
    {
        for(j=0;j<i;j++)
            if(arr[i]>arr[j])
                temp[i]+=temp[j] ;
    }
   
    sum=0 ;
    for(i=0;i<no;i++)
        sum=sum+temp[i] ;
   
    return sum ;
}

---------------------------------------------------------------------------------

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