Strong Number

PROBLEM :
Write a program to check whether a number is strong or not. A number is called strong number if sum of the factorial of its digit is equal to number itself. For example: 145 as 1! + 4! + 5! = 1 + 24 + 120 = 145

Input:
First line contains number of test cases T. Then following T lines contains an integer N.

Output:
Output "Strong" if given number is strong else "Not Strong" .

Constraints:
1<=T<=50
0<=N<=1000

Example:
Input:
2
145
10

Output:
Strong
Not Strong

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int Is_Strong(int ) ;
int factorial(int ) ;
int main()
 {
int t,no ;
cin>>t ;
while(t--)
{
   cin>>no ;
   if(Is_Strong(no))
       cout<<"Strong" ;
   else
       cout<<"Not Strong" ;
   cout<<endl ;
}
return 0;
}

int Is_Strong(int no)
{
    int r,sum,k ;
    sum=0 ;
    k=no ;
   
    while(no)
    {
        r=no%10 ;
        sum=sum+factorial(r) ;
        no=no/10 ;
    }
   
    if(k==sum)
        return 1 ;
    return 0 ;
}

int factorial(int no)
{
    int i,sum ;
    sum=1 ;
    if(no==0||no==1)
        return 1 ;
   
    for(i=1;i<=no;i++)
        sum=sum*i ;
       
    return sum ;
}

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