Min Subsets with Consecutive Numbers

PROBLEM :
Given an array of distinct positive numbers, the task is to calculate the number of subsets (or subsequences) from the array such that each subset contains consecutive numbers.

Input:
The first line of input contains an integer T denoting the no of test cases. Then T test cases follow. Each test case contains an integer N, denoting the length of the array. Next line contains N space seperated integers of the array.

Output:
For each test case output a new line denoting count of number of such subset's that contains consecutive numbers.
Constraints:
1<=T<=100
1<=N<=50

Example:
Input
2
11
100 56 5 6 102 58 101 57 7 103 5
3
10 100 105

Output
3
3

Explanation
Test Case 1 -
{5, 6, 7}, { 56, 57, 58, 59}, {100, 101, 102, 103} are 3 subset in which numbers are consecutive.

Test Case 2 -
{10}, {100} and {105} are 3 subset in which numbers are consecutive.

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/#include<iostream>
using namespace std;
#include<algorithm>
int Subsets_with_Consecutive(int [],int ) ;
int main()
 {
int t,no,i ;
int arr[100] ;
cin>>t ;
while(t--)
{
   cin>>no ;
   for(i=0;i<no;i++)
       cin>>arr[i] ;
     
   cout<<Subsets_with_Consecutive(arr,no) ;
   cout<<endl ;
}
return 0;
}

int Subsets_with_Consecutive(int arr[],int no)
{
    int i,count ;
    sort(arr,arr+no) ;
    count=1 ;
   
    for(i=0;i<no-1;i++)
    {
        if(arr[i+1]-arr[i]>1)
           count++ ;
    }
    return count ;
}

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