Find Number of Numbers

PROBLEM :
Given an array A[]  of n elements. Your task is to complete the Function num which returns an integer denoting the total number of times digit k appears in the whole array.

For Example:
A[]={11,12,13,14,15}, k=1

Output=6 //Count of the digit 1 in the array

Input:
The first line of input contains an integer T denoting the no of test cases. Then T test cases follow. The first line of each test case contain an integer n denoting the size of the array A[]. Then in the second line are n space separated values of the array A[] .In the third line of each test case contains an integer k, which is the digit to be counted.

Output:
For each test case in a new line print the number of elements counted.

Constraints:
1<=T<=100
1<=n<=20
1<=A[]<=1000

Example(To be used for expected output):
Input:
2
5
11 12 13 14 15
1
4
0 10 20 30
0

Output:
6
4

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/*Complete the function given below*/

int num(int a[], int n, int k)
{
    int i,r,count ;
    count=0 ;
    for(i=0;i<n;i++)
    {
        if(a[i]==0&&k==0)
         count++ ;
       
        while(a[i])
        {
            r=a[i]%10 ;
            if(r==k)
                count++ ;
            a[i]=a[i]/10 ;
        }
    }
   
    return count ;
}

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