Next sparse binary number

PROBLEM :
Given an integer n in the input, find its next sparse binary number.A sparse binary number is a number whose binary representation does not contain any consecutive 1s.

Input:
The first line of input contains an integer T denoting the number of test cases. The first line of each test case is number 'N'

Output:
Print next Sparse binary number,if the input number is not sparse else print the number itself.

Constraints:
1 = T = 100
1 = n = 100000

Example:
Input
2
3
5

Output
4
5

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SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int  Next_sparse_binary_number(int ) ;
int sparse(int ) ;
int main()
 {
int t,no ;
cin>>t ;
while(t--)
{
   cin>>no ;
   cout<<Next_sparse_binary_number(no)<<endl ;
}
return 0;
}

int  Next_sparse_binary_number(int no)
{
    while(1)
    {
        if(sparse(no))
            return no ;
        else
            no++ ;
    }
}

int sparse(int no)
{
    int last,curr ;
    last=0,curr=0 ;
   
    while(no)
    {
        curr=no%2 ;
        if(curr==1&&last==1)
            return 0 ;
        no=no/2 ;
        last=curr ;
    }
    return 1 ;
}

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