Sum of two numbers represented as arrays

PROBLEM :

Given two numbers represented by two arrays, write a function that returns sum array. The sum array is an array representation of addition of two input arrays. It is not allowed to modify the arrays.

Input:

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case contains two integers M and N separated by a space. M is the size of arr1 and N is the size of arr2.
The second line of each test case contains M integers which is the input for arr1.
The third line of each test case contains N integers which is the input for arr2.

Output:

Print the sum list.

Constraints:

1 = T = 100
1 = N = M = 1000
0 = arr1[i],arr2[i]= 9

Example:

Input:
2
3 3
5 6 3
8 4 2
16 4
2 2 7 5 3 3 7 3 3 6 8 3 0 5 0 6
4 3 3 8

Output:
1 4 0 5
2 2 7 5 3 3 7 3 3 6 8 3 4 8 4 4

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int Sum_of_two_numbers(int [],int [],int [],int ,int ) ;
void reverse(int [],int ) ;
int main()
 {
int t,arr1[1000],arr2[1000],n1,n2,i ;
cin>>t ;
while(t--)
{
   cin>>n1>>n2 ;
 
   for(i=0;i<n1;i++)
       cin>>arr1[i] ;
   for(i=0;i<n2;i++)
       cin>>arr2[i]  ;
     
   int arr3[1001]={0} ;
 
   int no=Sum_of_two_numbers(arr1,arr2,arr3,n1,n2) ;
 
   reverse(arr3,no) ;
 
   for(i=0;i<=no;i++)
       cout<<arr3[i]<<" " ;
   cout<<endl ;
}
return 0;
}

int Sum_of_two_numbers(int a[],int b[],int c[],int n1,int n2)
{
    int k,carry ;
    k=0 ;
    carry=0 ;
   
    while(n1!=0&&n2!=0)
    {
        c[k]=a[--n1]+b[--n2]+carry ;
        carry=c[k]/10 ;
        c[k]=c[k]%10 ;
        k++ ;
    }
   
    if(n1!=0)
        while(n1!=0)
        {
            c[k]=a[--n1]+carry ;
            carry=c[k]/10 ;
            c[k]=c[k]%10 ;
            k++ ;
        }
       
    if(n2!=0)
        while(n2!=0)
        {
            c[k]=a[--n2]+carry ;
            carry=c[k]/10 ;
            c[k]=c[k]%10 ;
            k++ ;
        }
       
    if(carry!=0)
        c[k++]=carry ;
   
    return k-1 ;
}

void reverse(int arr[],int no)
{
    int i,j,temp ;
    i=0;
    j=no ;
   
    while(i<j)
    {
        temp=arr[i] ;
        arr[i]=arr[j] ;
        arr[j]=temp ;
        i++ ;
        j-- ;
    }
}                              

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