Spirally traversing a matrix

PROBLEM :

Traverse a 4x4 matrix of integers in spiral form.

Input: The first line of input contains an integer T denoting the number of test cases. First four lines of the test case will contain four elements each.
Output: Spiral array will be displayed in a single line.

Constraints:
1 <=T<= 100
1 <=N<= 100

Example:

Input:
1
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16

Output:
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10

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SIMPLE c++ IMPLEMENTATION :
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#include<iostream>
using namespace std;
#define MAX 4
void Spirally_traversing_matrix(int [MAX][MAX]) ;
int main()
 {
int t,i,j;
int mat[MAX][MAX] ;
cin>>t ;
while(t--)
{
   for(i=0;i<4;i++)
       for(j=0;j<4;j++)
           cin>>mat[i][j] ;
           
   Spirally_traversing_matrix(mat) ;
   cout<<endl ;
}
return 0;
}

void Spirally_traversing_matrix(int mat[MAX][MAX])
{
    int i,a,b,c,d,no ;
   
    no=4 ;
    for(i=0;i<no/2;i++)
    {
        for(a=i;a<no-i*1;a++)
            cout<<mat[i][a]<<" " ;
       
        for(b=i+1;b<no-i*1;b++)
            cout<<mat[b][no-1-i]<<" " ;
           
        for(c=no-2-i;c>=0+i;c--)
            cout<<mat[no-1-i][c]<<" " ;
           
        for(d=no-2-i;d>=0+1+i;d--)
            cout<<mat[d][i]<<" " ;
    }
}

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