Missing ranges of numbers

PROBLEM :

Given an array A[ ] of N positive integers, print out the missing elements in the range [0 - 999].If
there are more than one missing, collate them using hyphen ( - ), otherwise just print the number.

Example:
 Input:   {88 3, 2, 400, 0, 10}
 Output:   [ 1 4-9 11-87 89-399 401-999 ]

Input
The first line of input contains an integer T denoting the number of test cases. Then T test cases
follow.
The first line of each test case contains a positive integer N, denoting the length of the array A[ ].
The second line of each test case contains a N space separated positive integers, denoting the
elements of the array A[ ].  

Output
Print out the range of missing number or the number itself  separated by space enclosed in square
brackets : [ n1 n2 n3-n6 n8-n9 ]

Constraints
1 <= T <= 100
0 <   N <= 30
0 <= A[ ] < 1000

Examples

Input
3
5
62 8 34 5 332
4
13 0 32 500
5
2 0 9 15 999

Output
[ 0-4 6-7 9-33 35-61 63-331 333-999 ]
[ 1-12 14-31 33-499 501-999 ]
[ 1 3-8 10-14 16-998 ]

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
void Missing_ranges_of_numbers(int [],int ) ;
int remove_dublicate(int [],int ) ;
void bubble(int [],int ) ;
int main()
 {
int t,no,arr[30],i ;
cin>>t ;
while(t--)
{
   cin>>no ;
   for(i=0;i<no;i++)
       cin>>arr[i] ;
     
   Missing_ranges_of_numbers(arr,no);
   cout<<endl ;
}
return 0;
}

void Missing_ranges_of_numbers(int arr[],int no)
{
    bubble(arr,no) ;
   
    no=remove_dublicate(arr,no) ;
   
    int i,beg,end ;
    beg=0 ;
   
    cout<<"[ " ;
    for(i=0;i<no;i++)
    {
        end=arr[i] ;
        if(beg!=end)
        {
            if(beg==end-1)
            {
                cout<<beg<<" " ;
                beg=arr[i]+1 ;
            }
            else
            {
                cout<<beg<<"-"<<end-1 ;
                beg=arr[i]+1 ;
               
                if(beg!=1000)
                    cout<<" " ;
            }
        }
        else
            beg=beg+1 ;
    }
    if(beg==999)
        cout<<"999" ;
    else if(beg!=1000)
        cout<<beg<<"-"<<"999" ;
       
    cout<<" ]" ;
}

void bubble(int a[],int no)
{
    int i,j,temp ;
    for(i=0;i<no-1;i++)
    {
        for(j=0;j<no-i-1;j++)
        {
            if(a[j]>a[j+1])
                {
                    temp=a[j] ;
                    a[j]=a[j+1] ;
                    a[j+1]=temp ;
                }
        }
    }
}

int remove_dublicate(int arr[],int no)
{
    int i,k ;
    k=0 ;
    for(i=1;i<no;i++)
    {
        if(arr[i]!=arr[k])
        {
            arr[++k]=arr[i] ;
        }
    }
    return k+1 ;
}

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