Count zeros in a sorted matrix

PROBLEM :

Given a N x N binary matrix A where each row and column of the matrix is sorted in ascending order , Your task is to complete the function  countZero which returns the count of  number of 0s present in it.

Note : Elements in matrix can be either 1 or 0

Input:
The first line of input will be the no of test cases then T test cases will follow . The second line of each test case contains two space separated integers M,N denoting the size of the 2 d matrix . Then in the next lines are the space separated values of the matrix A[ ] [ ] .

Output:
The output will be the number of zeroes present in the square matrix.

Constraints:
1<=T<=50
1<=M,N<=50
0<=A[][]<=1

Example:

Input
1
3
0 0 0 0 0 1 0 1 1

Output
6

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SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/*you are required to complete this method*/

int countZeroes(int A[MAX][MAX],int N)
{
    int i,j,count ;
    count=0 ;
   
    for(i=0;i<N;i++)
    {
        for(j=0;j<N;j++)
        {
            if(A[i][j]==0)
                count++ ;
            else
                break ;
        }
    }
    return count ;
}


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