Sum of primes

PROBLEM :

Your task is to calculate sum  of primes in a digit N.

Input:

The first line of input contains an integer T denoting the number of test cases. Then T test cases follow. The next T lines contains an integer N.

Output:
Print sum of primes in the digit

Constraints:
1 = T = 50
1 = N = 50000


Example:

Input:

2
333
686

Output:
9
0
     
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
bool isPrime(int ) ;
int main()
 {
int t,no,sum,rem ;
cin>>t ;
while(t--)
{
   cin>>no ;
   sum=0 ;
 
   while(no!=0)
   {
       rem=no%10 ;
       if(isPrime(rem))
       {
           sum=sum+rem ;
       }
       no=no/10 ;
   }
   cout<<sum<<endl ;
}
return 0;
}

bool isPrime(int no)
{
    int i ;
    if(no==1)
        return false ;
       
    for(i=2;i<no;i++)
    {
        if(no%i==0)
            return false ;
    }
    return true ;
}

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