Count number of hops

PROBLEM :

Frog steps either 1, 2 or 3 steps to go to top. In how many ways it reaches the top?

Input:

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N. Where is the number of steps it has to hop.

Output:

Print the number of ways.

Constraints:
1 = T = 50
1 = N = 50

Example:

Input:
2
1
5

Output:
1
13

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
long long number_of_hops(long long ) ;
int main()
 {
int t ;
long long no ;
cin>>t ;
while(t--)
{
   cin>>no ;
 
   no=number_of_hops(no) ;
   cout<<no<<endl ;
}
return 0;
}

long long number_of_hops(long long no)
{
    no=no+1 ;
    long long arr[no] ;
    int i ;
   
    arr[0]=1 ;
    arr[1]=1 ;
    arr[2]=2 ;
   
    if(no>=3)
    for(i=3;i<=no;i++)
        arr[i]=arr[i-1]+arr[i-2]+arr[i-3] ;

    return arr[no-1] ;
}

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