Sort linked list which is already sorted on absolute values

PROBLEM :

Given a linked list L of N nodes, sorted in ascending order based on the absolute values of its data. Sort the linked list according to the actual values.
Ex: Input : 1 -> -2 -> -3 -> 4 -> -5
      Output: -5 -> -3 -> -2 -> 1 -> 4

Input
The first line of input contains an integer T denoting the number of test cases. Then T test cases follow. Each test case consists of two lines. The first line of each test case contains a positive integer N denoting the size of linked list. The second line of each test case contains N space separated integers denoting the values of N nodes.


Output
Corresponding to each test case, print out the sorted linked list.


Constraints
1 <= T <= 100
0 <   N  <= 30
-100 <= L[i] <= 100

Examples

Input
2
3
1 -3 -4
4
0 -2 3 -10


Output
-4  -3  1
-10 -2  0  3

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/* The structure of the Linked list Node is as follows:
struct Node
{
    Node* next;
    int data;
}; */

void sortList(Node** head)
{
    struct Node *temp,*small ;
   
    if((*head)==NULL)
    return ;
    temp=(*head) ;
   
    while(temp->next!=NULL)
    {
        if(temp->data>temp->next->data)
        {
            small=temp->next ;
            temp->next=small->next ;
            small->next=(*head) ;
            (*head)=small ;
        }
        else
            temp=temp->next ;
    }
}

---------------------------------------------------------------------------------

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