Delete N nodes after M nodes of a linked list

PROBLEM :

Given a linked list, delete N nodes after skipping M nodes of a linked list until the last of the linked list.

Input:

Complete the method which takes three argument: the head of the linked list,M an N. Function should not read any input from stdin/console.
The struct Node has a data part which stores the data and a next pointer which points to the next element of the linked list.
There are multiple test cases. For each test case, this method will be called individually.


Output:

Function should not print any output to stdin/console


Example:

Input:
M = 2, N = 2
Linked List: 1->2->3->4->5->6->7->8
Output:
Linked List: 1->2->5->6

Input:
M = 3, N = 2
Linked List: 1->2->3->4->5->6->7->8->9->10
Output:
Linked List: 1->2->3->6->7->8

Input:
M = 1, N = 1
Linked List: 1->2->3->4->5->6->7->8->9->10
Output:
Linked List: 1->3->5->7->9

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/*
delete n nodes after m nodes
  The input list will have at least one element
  Node is defined as
  struct node
  {
     int data;
     struct node *next;
  }

*/

void linkdelete(struct node  *head, int M, int N)
{
    if(head==NULL)
        return ;
       
    int i ;  
    struct node *m,*n ;
   
    m=head ;
    n=head ;
   
    while(1)
    {
        i=1 ;
        while(m->next!=NULL&&i!=M)
        {
            m=m->next ;
            i++ ;
        }
       
        i=0 ;
        while(m!=NULL&&m->next!=NULL&&i!=N)
        {
            n=m->next ;
            m->next=n->next ;
            free(n) ;
            i++ ;
        }
       
        if(m->next)
            m=m->next ;
        if(m==NULL||m->next==NULL)
        break ;
    }
}



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