Change a Binary Tree so that every node stores sum of all nodes in left subtree

PROBLEM :

Given a Binary Tree, change the value in each node to sum of all the values in the nodes in the left subtree including its own.

Example

Input :
     1
   /   \
 2      3

Output :
    3
  /   \
 2     3


Input
       1
      / \
     2   3
    / \   \
   4   5   6
Output:
      12
     / \
    6   3
   / \   \
  4   5   6

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/*
typedef struct BST
{
int info ;
struct BST *left ;
struct BST *right ;
}tree ;---------------------------------------------*/

int BST_left_subTreeSum(tree *root)
{
if(root==NULL)
return 0 ;

if(root->left==NULL&&root->right==NULL)
return root->info ;

int sumL,sumR ;
sumL=BST_left_subTreeSum(root->left) ;
sumR=BST_left_subTreeSum(root->right) ;

root->info=root->info+sumL ;

return root->info+sumR ;
}

---------------------------------------------------------------------------------

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