Compare two strings represented as linked lists

PROBLEM :

Given two string, represented as linked lists (every character is a node in linked list). Write a function compare() that works similar to strcmp(), i.e., it returns 0 if both strings are same, 1 if first linked list is lexicographically greater, and -1 if second is lexicographically greater.

Input:

In this problem, method takes two argument: the head of the first and second linked list. The function should not read any input from stdin/console.
The struct Node has a data part which stores the data and a next pointer which points to the next element of the linked list.
There are multiple test cases. For each test case, this method will be called individually.

Output:

Comapare two strings represented as linked list.

Constraints:

1<=T<=100

1<=N,M<=100

Example:
Input:
2
5
a b a b a
4
a b a a
3
a a b
3
a a b

Output:
1
0

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/* Linked list Node structure
struct Node
{
    char c;
    struct Node *next;
}; */

// Compare two strings represented as linked lists
int compare(Node *list1, Node *list2)
{
     if(list1==NULL&&list2==NULL)
        return 0 ;
    if(list1!=NULL&&list2==NULL)
        return 1 ;
    if(list1==NULL&&list2!=NULL)
        return -1 ;
       
    if(list1->c==list2->c)
        return(compare(list1->next,list2->next)) ;
    else if(list1->c>list2->c)
        return 1 ;
    else
        return -1 ;
       
}

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