Maximum Difference

PROBLEM :
Given an array C[] of integers, find out the maximum difference between any two elements such that larger element appears after the smaller number in C[].
Examples: If array is [2, 3, 10, 6, 4, 8, 1] then returned value should be 8 (Diff between 10 and 2). If array is [ 7, 9, 5, 6, 3, 2 ] then returned value should be 2 (Diff between 7 and 9).

Input:
The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N,N is the size of array.
The second line of each test case contains N input C[i].

Output:
Print the maximum difference between two element. Otherwise print -1

Constraints:
1 = T = 80
2 = N = 100
1 = C[i] = 500

Example:
Input:
2
7
2 3 10 6 4 8 1
5
1 2 90 10 110

Output:
8
109

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int main()
{
int t ;
cin>>t ;
while(t--)
{
   int no ;
   cin>>no ;
   int arr[no] ;
   for(int i=0;i<no;i++)
       cin>>arr[i] ;
 
   int diff[no-1] ;
   for(int i=0;i<no-1;i++)
       diff[i]=arr[i+1]-arr[i] ;
     
   int maxdiff=diff[0] ;
   for(int i=1;i<no-1;i++)
   {
       if(diff[i]+diff[i-1]>diff[i])
           diff[i]=diff[i]+diff[i-1] ;
     
       if(diff[i]>maxdiff)
           maxdiff=diff[i] ;
   }
 
   cout<<maxdiff<<endl ;
}
return 0;
}

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION : O(n)  time O(1) space
--------------------------------------------------------------------------------

#include<bits/stdc++.h>
using namespace std;
int main()
{
int t ;
cin>>t ;
while(t--)
{
   int no ;
   cin>>no ;
   int arr[no] ;
   for(int i=0;i<no;i++)
       cin>>arr[i] ;
 
   int minSoFar=arr[0] ;
   int maxDiff=INT_MIN ;
 
   for(int i=1;i<no;i++)
   {
       int curr=arr[i]-minSoFar ;
     
       if(curr>maxDiff)
           maxDiff=curr ;
       if(arr[i]<minSoFar)
           minSoFar=arr[i] ;
   }
 
   cout<<maxDiff<<endl ;
}
return 0;
}

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