Substring - Subsequence problem

PROBLEM :
Manoj, Vinoj and Jegan are the famous coders of TCE. One fine day Vinoj and Jegan challenge Manoj to solve a puzzle. That is Vinoj will select one string A. Similarly Jegan will choose one string B with the same size. You need to help Manoj to find the longest subsequence X of a string A which is a substring Y of a string B.

Example
A : ABCD
B : BACDBDCD
The answer would be 3 as because 'ACD' is the longest subsequence of A which is also a substring of B.

Input:
The first line of input contains an integer T. Then T test cases follow. Each test case contains two space separated strings A and B.

Output:
For each test case in a new line print the required output.

Constraints:
1<=T<=12
1<=Length of strings <=100

Example:
Input:
2
ABCD BACDBDCD
A A

Output:
3
1

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
#include<string.h>
int Subsequence(string ,string ) ;
int main()
{
int t ;
string s1,s2 ;
cin>>t ;
while(t--)
{
   cin>>s1>>s2 ;
   cout<<Subsequence(s1,s2)<<endl ;
}
return 0;
}

int Subsequence(string s1,string s2)
{
    int l1,l2,max,i,j ;
    l1=s1.length() ;
    l2=s2.length() ;
   
    int mat[l2+1][l1+1] ;
    max=0 ;
   
    for(i=0;i<=l2;i++)
        mat[i][0]=0 ;
       
    for(i=0;i<=l1;i++)
        mat[0][i]=0 ;
       
    for(i=1;i<=l2;i++)
    {
        for(j=1;j<=l1;j++)
        {
            if(s2[i-1]==s1[j-1])
                mat[i][j]=mat[i-1][j-1]+1 ;
            else
                mat[i][j]=mat[i][j-1] ;
               
            if(mat[i][j]>max)
                max=mat[i][j] ;
        }
    }
    return max ;
}

---------------------------------------------------------------------------------

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