1[0]1 Pattern Count

PROBLEM :
Given a string, your task is to find the number of patterns of form 1[0]1 where [0] represents any number of zeroes (minimum requirement is one 0) there should not be any other character except 0 in the [0] sequence.

Input:
The first line contains T denoting the number of testcases. Then follows description of testcases. Each case contains a string.

Output:
For each test case, output the number of patterns.

Constraints:
1<=T<=20
1<=Length of String<=2000

Example:
Input:
2
100001abc101
1001ab010abc01001

Output:
2
2

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SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
#include<string.h>
int PatternCount(string ) ;
int main()
{
int t ;
string str ;
cin>>t ;
while(t--){
   cin>>str ;
   cout<<PatternCount(str)<<endl ;
}
return 0;
}

int PatternCount(string str){
    bool flag=false ;
    int len,count ;
    len=str.length() ;
    count=0 ;
   
    for(int i=0;i<len;i++){
        if(str[i]=='1'&&flag==false)
            flag=true ;
        else if(str[i]!='0'&&str[i]!='1')
            flag=false ;
        else if(str[i]=='1'&&flag==true){
            if(str[i-1]=='0')
                count++ ;
        }
    }
    return count ;
}

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