Numbers containing 0's from 1 to N
PROBLEM : Efficiently count how many integers from 1 to N contains 0's as a digit. Input: First line of the input contains the number of test cases T. Each line of test case contains the integer N. Output: Number of integers that contain 0 as a digit are printed. Constraints: 1 <=T<= 100 1 <=N<= 10000 Example: Input: 3 100 987 20 Output: 10 179 2 -------------------------------------------------------------------------------- SIMPLE c++ IMPLEMENTATION : -------------------------------------------------------------------------------- #include<iostream> using namespace std; int count_zeroes(int ) ; int main() { int t,no ; cin>>t ; while(t--) { cin>>no ; cout<<count_zeroes(no)<<endl ; } return 0; } int count_zeroes(int no) { int i,count ; ...