Maximum of all subarrays of size k

PROBLEM :

Given an array and an integer k, find the maximum for each and every contiguous subarray of size k.

Input:
The first line of input contains an integer T denoting the number of test cases. The description of T test cases follows.
The first line of each test case contains a single integer 'N' denoting the size of array and the size of subarray 'k'.
The second line contains 'N' space-separated integers A1, A2, ..., AN denoting the elements of the array.

Output:
Print the maximum for every subarray of size k.

Constraints:
1 = T = 100
1 = N = 100
1 = k = N
0 =A[i]<1000

Example:

Input:
2
9 3
1 2 3 1 4 5 2 3 6
10 4
8 5 10 7 9 4 15 12 90 13

Output:
3 3 4 5 5 5 6
10 10 10 15 15 90 90

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
void Maximum_of_all_subarrays(int [],int ,int ) ;
int max_of(int ,int ) ;
int main()
 {
int t,no,k,arr[100],i ;
cin>>t ;
while(t--)
{
   cin>>no>>k ;
 
   for(i=0;i<no;i++)
       cin>>arr[i] ;
     
   Maximum_of_all_subarrays(arr,no,k) ;
   cout<<endl ;
}
return 0;
}

void Maximum_of_all_subarrays(int arr[],int no,int k)
{
    int i,max,check ;
    int temp1[no],temp2[no] ;
 

    check=1 ;
    max=arr[0] ;
    for(i=0;i<no;i++)
    {
        if(check>k)
        {
            check=1 ;
            max=arr[i] ;
        }
        if(arr[i]>max)
            max=arr[i] ;
         
        temp1[i]=max ;
        check++ ;
    }
 
    max=arr[no-1] ;
    for(i=no-1;i>=no-no%k;i--)
    {
        if(arr[i]>max)
            max=arr[i] ;
         
        temp2[i]=max ;
    }                                
 
    check=1 ;
    max=arr[i] ;
    for(i;i>=0;i--)
    {
        if(check>k)
        {
            check=1 ;
            max=arr[i] ;
        }
        if(arr[i]>max)
            max=arr[i] ;
         
        temp2[i]=max ;
        check++ ;
    }

    for(i=0;i<no-k+1;i++)
        cout<<max_of(temp1[i+k-1],temp2[i])<<" " ;
}

int max_of(int a,int b)
{
    return a>b?a:b ;
}

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