Binary Search Tree Iterator @LeetCode
PROBLEM :
Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next() will return the next smallest number in the BST.
Note: next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
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SIMPLE c++ IMPLEMENTATION :
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/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class BSTIterator {
stack<TreeNode *> sta ;
public:
BSTIterator(TreeNode *root) {
pushLeft(root) ;
}
/** @return whether we have a next smallest number */
bool hasNext() {
if(sta.empty())
return false ;
return true ;
}
/** @return the next smallest number */
int next() {
TreeNode *curr=sta.top() ;
sta.pop() ;
if(curr->right)
pushLeft(curr->right) ;
return curr->val ;
}
void pushLeft(TreeNode *root){
TreeNode *ptr=root ;
while(ptr){
sta.push(ptr) ;
ptr=ptr->left ;
}
}
};
/**
* Your BSTIterator will be called like this:
* BSTIterator i = BSTIterator(root);
* while (i.hasNext()) cout << i.next();
*/
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Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next() will return the next smallest number in the BST.
Note: next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class BSTIterator {
stack<TreeNode *> sta ;
public:
BSTIterator(TreeNode *root) {
pushLeft(root) ;
}
/** @return whether we have a next smallest number */
bool hasNext() {
if(sta.empty())
return false ;
return true ;
}
/** @return the next smallest number */
int next() {
TreeNode *curr=sta.top() ;
sta.pop() ;
if(curr->right)
pushLeft(curr->right) ;
return curr->val ;
}
void pushLeft(TreeNode *root){
TreeNode *ptr=root ;
while(ptr){
sta.push(ptr) ;
ptr=ptr->left ;
}
}
};
/**
* Your BSTIterator will be called like this:
* BSTIterator i = BSTIterator(root);
* while (i.hasNext()) cout << i.next();
*/
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