Student record
PROBLEM :
A file contains data as follows( Student name, marks in 3 subjects)
Shrikanth 20 50 60
Kiran 30 80 90
Find the student who has maximum average score.
Input:
The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N,N is the number of student.
The second line of each test case contains N input Student name and marks in 3 subject.
Output:
Print the student who has maximum average score and maximum average score(in int).
Constraints:
1 = T = 10
1 = N = 15
1 = s = 10
1 = marks = 100
Example:
Input:
2
2
Shrikanth 20 30 10 Ram 100 50 10
3
Adam 50 10 40 Suresh 22 1 56 Rocky 100 90 10
Output:
Ram 53
Rocky 66
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
#include<iostream>
using namespace std;
#include<string.h>
class student
{
string name ;
int n1,n2,n3 ;
public:
void getInput()
{
cin>>name ;
cin>>n1>>n2>>n3 ;
}
int getMaxAvg()
{
int sum ;
sum=n1+n2+n3 ;
return sum/3 ;
}
string Rname()
{
return name ;
}
} ;
int main()
{
int t,no,i,avg ;
int mavg ;
string name ;
cin>>t ;
while(t--)
{
cin>>no ;
student s[no] ;
mavg=0 ;
name="" ;
for(i=0;i<no;i++)
s[i].getInput() ;
for(i=0;i<no;i++)
{
avg=s[i].getMaxAvg() ;
if(avg>mavg)
{
mavg=avg ;
name=s[i].Rname() ;
}
}
cout<<name<<" "<<mavg<<endl ;
}
return 0;
}
---------------------------------------------------------------------------------
A file contains data as follows( Student name, marks in 3 subjects)
Shrikanth 20 50 60
Kiran 30 80 90
Find the student who has maximum average score.
Input:
The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N,N is the number of student.
The second line of each test case contains N input Student name and marks in 3 subject.
Output:
Print the student who has maximum average score and maximum average score(in int).
Constraints:
1 = T = 10
1 = N = 15
1 = s = 10
1 = marks = 100
Example:
Input:
2
2
Shrikanth 20 30 10 Ram 100 50 10
3
Adam 50 10 40 Suresh 22 1 56 Rocky 100 90 10
Output:
Ram 53
Rocky 66
--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------
#include<iostream>
using namespace std;
#include<string.h>
class student
{
string name ;
int n1,n2,n3 ;
public:
void getInput()
{
cin>>name ;
cin>>n1>>n2>>n3 ;
}
int getMaxAvg()
{
int sum ;
sum=n1+n2+n3 ;
return sum/3 ;
}
string Rname()
{
return name ;
}
} ;
int main()
{
int t,no,i,avg ;
int mavg ;
string name ;
cin>>t ;
while(t--)
{
cin>>no ;
student s[no] ;
mavg=0 ;
name="" ;
for(i=0;i<no;i++)
s[i].getInput() ;
for(i=0;i<no;i++)
{
avg=s[i].getMaxAvg() ;
if(avg>mavg)
{
mavg=avg ;
name=s[i].Rname() ;
}
}
cout<<name<<" "<<mavg<<endl ;
}
return 0;
}
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