Print all nodes that don’t have sibling

PROBLEM :

Given a Binary Tree your task is to print the nodes  which dont have a sibling node . You are required to complete the function printSibling. You should not read any input from stdin/console. There are multiple test cases. For each test case, this method will be called individually.

Input:
The task is to complete the function printSibling which takes 1 argument, root of the Tree .The struct node has a data part which stores the data, pointer to left child and pointer to right child.
There are multiple test cases. For each test case, this method will be called individually.

Output:
The function should print all the nodes separated by space which don't have sibling in the tree.

Constraints:
1 <=T<= 30
1 <=Number of nodes<= 100
1 <=Data of a node<= 1000

For example, the output should be “4 5 6? for the following tree.



--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/* Tree node structure  used in the program
 struct Node
 {
     int data;
     struct Node* left, *right;
}; */

/* Prints the nodes having no siblings.  */


void printSibling(struct Node* root)
{
   if(root==NULL)
    return ;
   
    if(root->left==NULL&&root->right==NULL)
    return ;
   
    if(root->left!=NULL&&root->right==NULL)
    cout<<root->left->data<<" " ;
   
    if(root->left==NULL&&root->right!=NULL)
    cout<<root->right->data<<" " ;
   
    printSibling(root->left) ;
    printSibling(root->right) ;
}

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