Facing the sun

PROBLEM :

An array of buildings is facing the sun. The heights of the building is given in an array. You have to tell which all buildings will see the sunset.

Input:

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N,N is the number of buildings.
The second line of each test case contains N input H[i],height of building.

Output:

Print the total number of buildings which will see the sunset.

Constraints:

1 = T = 100
1 = N = 500
1 = H[i] = 1000

Example:

Input:
2
5
7 4 8 2 9
4
2 3 4 5

Output:
3
4

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int main()
 {
int t,no,a[1000],i,top,count ;
cin>>t ;
while(t--)
{
   cin>>no ;
   for(i=0;i<no;i++)
   cin>>a[i] ;
   count=1 ;
   top=a[0] ;
   for(i=0;i<no;i++)
   {
       if(a[i]>top)
       {top=a[i];count++ ;}
   }
 
   cout<<count<<endl ;
}
return 0;
}

---------------------------------------------------------------------------------

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