Count the numbers

PROBLEM :

Given a number N, count the numbers from 1 to N which comprise of digits, only in set 1, 2, 3, 4 and 5.

Input:

The first line of input contains an integer T denoting the number of test cases.Then T test cases follow. Each test case consist of one line. Each line of each test case is N, where N is the range from 1 to N.

Output:

Print the count of numbers in the given range from 1 to N.

Constraints:

1 = T = 100
1 = N = 1000

Example:

Input:
2
100
10
Output:
30
5


Explanation:

When n is 20 then answer is 10 because 1 2 3 4 5 11 12 13 14 15 are only in given set. 16 is not beause 6 is not in given set, only 1 2 3 4 5 in set.

--------------------------------------------------------------------------------
Simple C++ Code :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
int call(int) ;
int main()
 {
int test,no,i,r,count  ;
cin>>test ;
while(test--)
{
   cin>>no ;
   count=0 ;
   r=0 ;
   for(i=1;i<=no;i++)
   {
       r=call(i) ;
     
       if(r==1)
           count++ ;
       else
        continue ;
         
   }
   cout<<count<<endl ;
}
return 0;
}
int call(int no)
{
    int r ;
lable :
    while(no!=0)
    {
    r=no%10 ;
   
        if(r==1||r==2||r==3||r==4||r==5)
        {
            no=no/10 ;
            goto lable ;
        }
        else
        return 0 ;
    }
    return 1 ;
}

-------------------------------------------------------------------------------

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