Sum of Middle Elements of two sorted arrays

PROBLEM :
Given 2 sorted arrays A and B of size N each. Print sum of middle elements of the array obtained after merging the given arrays.

Input:
The first line contains 'T' denoting the number of testcases. Then follows description of testcases.
Each case begins with a single positive integer N denoting the size of array.
The second line contains the N space separated positive integers denoting the elements of array A.
The third line contains N space separated positive integers denoting the elements of array B.

Output:

For each testcase, print the sum of middle elements of two sorted arrays. The number of the elements in the merged array are even so there will be 2 numbers in the center n/2 and n/2 +1. You have to print their sum.

Constraints:
 1<=T<=50
 1<=N<=1000
 1<=A[i]<=100000
 1<=B[i]<=100000

Example:
Input :
1
5
1 2 4 6 10
4 5 6 9 12

Output :
11

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

#include<iostream>
using namespace std;
#define max 1000
int Middle_Elements_sum(int [],int [],int ) ;
int main()
 {
int t,arr1[max],arr2[max],no,i ;
cin>>t ;
while(t--)
{
   cin>>no ;
   for(i=0;i<no;i++)
       cin>>arr1[i] ;
   for(i=0;i<no;i++)
       cin>>arr2[i] ;
     
   cout<<Middle_Elements_sum(arr1,arr2,no)<<endl ;
}
return 0;
}

int Middle_Elements_sum(int arr1[],int arr2[],int no)
{
    int i,j,k ;
    k=no-1 ;
    i=0 ;
    j=0 ;
   
    while(k)
    {
        if(arr1[i]==arr2[j])
        {
            i++ ;
            j++ ;
            k-- ;
            k-- ;
        }
        else if(arr1[i]<arr2[j])
        {
            i++ ;
            k-- ;
        }
        else
        {
            j++ ;
            k-- ;
        }
    }
   
    if(arr1[i]<arr2[j]&&arr1[i+1]<arr2[j])
        return arr1[i]+arr1[i+1] ;
   
    if(arr1[i]>arr2[j]&&arr1[i]>arr2[j+1])
        return arr2[j]+arr2[j+1] ;
       
    return arr1[i]+arr2[j] ;
}

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