Leaf at same level

PROBLEM :

Given a Binary Tree, check if all leaves are at same level or not.

          12
        /    \
      5       7      
    /          \
   3            1
  Leaves are at same level

          12
        /    \
      5       7      
    /        
   3        
   Leaves are Not at same level


          12
        /  
      5            
    /   \      
   3     9
  /      /
 1      2
 Leaves are at same level

Input:
The task is to complete the method that takes one argument, root of Binary Tree and returns 1 if all leaves are at same level else returns 0

Output:
Output for each test case will be 0 if all leaves are not at same level else it will 1.

Constraints:
1 <=T<= 30
1 <= Number of nodes<= 100
1 <= Data of a node<= 1000

Example(To be used only for expected output):
Input
2
2
1 2 R 1 3 L
4
10 20 L 10 30 R 20 40 L 20 60 R

Output
1
0

--------------------------------------------------------------------------------
SIMPLE c++ IMPLEMENTATION :
--------------------------------------------------------------------------------

/* The structure of the binary tree is as follows
struct Node
{
    int data;
    struct Node* left;
    struct Node* right;
};
*/

/*You are required to complete this method*/

int Height(Node *) ;
bool level(Node *,int ) ;

bool check(Node *root)
{
    if(root==NULL)
        return true ;
       
    int h ;
    h=Height(root) ;
    int i ;
    bool c=true ;
   
    for(i=0;i<h;i++)
    {
        c=level(root,i) ;
        if((i+1)!=h&&c!=true)
            return false ;
    }
    return true ;
}

int Height(Node *root)
{
    if(root==NULL)
        return 0 ;
       
    int l,r ;
    l=Height(root->left) ;
    r=Height(root->right) ;
   
    return l>r?(l+1):(r+1) ;
}

bool level(Node *root,int l)
{
    if(root==NULL)
        return true ;
       
    if(l==0)
    {
        if(root->left==NULL&&root->right==NULL)
            return false ;
        else
            return true ;
    }
   
    return level(root->left,l-1)&&level(root->right,l-1) ;
}

---------------------------------------------------------------------------------

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